std::ranges::count,std::ranges::count_if
在头文件中定义 <algorithm> |
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调用签名 |
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(1) | ||
template< std::input_iterator I, std::sentinel_for<I> S, class T, class Proj = std::identity > requires std::indirect_binary_predicate <ranges::equal_to, std::projected<I, Proj>, const T*> constexpr std::iter_difference_t<I> count( I first, S last, const T& value, Proj proj = {} ); |
(自 C++20 起) (直到 C++26) |
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template< std::input_iterator I, std::sentinel_for<I> S, class Proj = std::identity, |
(自 C++26 起) | |
(2) | ||
template< ranges::input_range R, class T, class Proj = std::identity > requires std::indirect_binary_predicate |
(自 C++20 起) (直到 C++26) |
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template< ranges::input_range R, class Proj = std::identity, class T = std::projected_value_t<ranges::iterator_t<R>, Proj> > |
(自 C++26 起) | |
template< std::input_iterator I, std::sentinel_for<I> S, class Proj = std::identity, |
(3) | (自 C++20 起) |
template< ranges::input_range R, class Proj = std::identity, std::indirect_unary_predicate< |
(4) | (自 C++20 起) |
返回范围内 [
first,
last)
满足特定条件的元素数量。
本页描述的函数式实体是 niebloids,也就是说
在实践中,它们可能通过函数对象或使用特殊的编译器扩展来实现。
内容 |
[编辑] 参数
first, last | - | 要检查的元素范围 |
r | - | 要检查的元素范围 |
value | - | 要搜索的值 |
pred | - | 要应用于投影元素的谓词 |
proj | - | 要应用于元素的投影 |
[编辑] 返回值
满足条件的元素数量。
[编辑] 复杂度
正好 last - first 次比较和投影。
[编辑] 备注
有关范围中没有其他条件的元素数量,请参阅 std::ranges::distance。
功能测试 宏 | 值 | Std | 功能 |
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__cpp_lib_algorithm_default_value_type |
202403 | (C++26) | 算法的 列表初始化 (1,2) |
[编辑] 可能的实现
count (1) |
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struct count_fn { template<std::input_iterator I, std::sentinel_for<I> S, class Proj = std::identity, class T = std::projected_value_t<I, Proj>> requires std::indirect_binary_predicate<ranges::equal_to, std::projected<I, Proj>, const T*> constexpr std::iter_difference_t<I> operator()(I first, S last, const T& value, Proj proj = {}) const { std::iter_difference_t<I> counter = 0; for (; first != last; ++first) if (std::invoke(proj, *first) == value) ++counter; return counter; } template<ranges::input_range R, class Proj = std::identity class T = std::projected_value_t<ranges::iterator_t<R>, Proj>> requires std::indirect_binary_predicate<ranges::equal_to, std::projected<ranges::iterator_t<R>, Proj>, const T*> constexpr ranges::range_difference_t<R> operator()(R&& r, const T& value, Proj proj = {}) const { return (*this)(ranges::begin(r), ranges::end(r), value, std::ref(proj)); } }; inline constexpr count_fn count; |
count_if (3) |
struct count_if_fn { template<std::input_iterator I, std::sentinel_for<I> S, class Proj = std::identity, std::indirect_unary_predicate<std::projected<I, Proj>> Pred> constexpr std::iter_difference_t<I> operator()(I first, S last, Pred pred, Proj proj = {}) const { std::iter_difference_t<I> counter = 0; for (; first != last; ++first) if (std::invoke(pred, std::invoke(proj, *first))) ++counter; return counter; } template<ranges::input_range R, class Proj = std::identity, std::indirect_unary_predicate< std::projected<ranges::iterator_t<R>, Proj>> Pred> constexpr ranges::range_difference_t<R> operator()(R&& r, Pred pred, Proj proj = {}) const { return (*this)(ranges::begin(r), ranges::end(r), std::ref(pred), std::ref(proj)); } }; inline constexpr count_if_fn count_if; |
[编辑] 示例
#include <algorithm> #include <cassert> #include <complex> #include <iostream> #include <vector> int main() { std::vector<int> v{1, 2, 3, 4, 4, 3, 7, 8, 9, 10}; namespace ranges = std::ranges; // determine how many integers in a std::vector match a target value. int target1 = 3; int target2 = 5; int num_items1 = ranges::count(v.begin(), v.end(), target1); int num_items2 = ranges::count(v, target2); std::cout << "number: " << target1 << " count: " << num_items1 << '\n'; std::cout << "number: " << target2 << " count: " << num_items2 << '\n'; // use a lambda expression to count elements divisible by 3. int num_items3 = ranges::count_if(v.begin(), v.end(), [](int i){ return i % 3 == 0; }); std::cout << "number divisible by three: " << num_items3 << '\n'; // use a lambda expression to count elements divisible by 11. int num_items11 = ranges::count_if(v, [](int i){ return i % 11 == 0; }); std::cout << "number divisible by eleven: " << num_items11 << '\n'; std::vector<std::complex<double>> nums{{4, 2}, {1, 3}, {4, 2}}; #ifdef __cpp_lib_algorithm_default_value_type auto c = ranges::count(nums, {4, 2}); #else auto c = ranges::count(nums, std::complex<double>{4, 2}); #endif assert(c == 2); }
输出
number: 3 count: 2 number: 5 count: 0 number divisible by three: 3 number divisible by eleven: 0
[编辑] 参见
(C++20) |
返回迭代器与哨兵之间的距离,或范围的起始位置与结束位置之间的距离 (niebloid) |
(C++20) |
从迭代器和计数创建一个子范围 (自定义点对象) |
一个 view ,它包含满足谓词的 range 中的元素(类模板) (范围适配器对象) | |
返回满足特定条件的元素数量 (函数模板) |