std::ranges::destroy
来自 cppreference.cn
定义于头文件 <memory> |
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调用签名 (Call signature) |
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template< no-throw-input-iterator I, no-throw-sentinel-for<I> S > requires std::destructible<std::iter_value_t<I>> |
(1) | (C++20 起) |
template< no-throw-input-range R > requires std::destructible<ranges::range_value_t<R>> |
(2) | (C++20 起) |
1) 销毁范围
[
first,
last)
中的对象,如同通过以下方式:for (; first != last; ++first) std::ranges::destroy_at(std::addressof(*first)); return first;
本页描述的类函数实体是 算法函数对象(非正式地称为 niebloids),即
目录 |
[编辑] 参数
first, last | - | 定义要销毁元素的范围的迭代器-哨兵对 |
r | - | 要销毁的range |
[编辑] 返回值
一个迭代器与 last 比较相等。
[编辑] 复杂度
与 first 和 last 之间的距离呈线性关系。
[编辑] 可能实现
struct destroy_fn { template<no-throw-input-iterator I, no-throw-sentinel-for<I> S> requires std::destructible<std::iter_value_t<I>> constexpr I operator()(I first, S last) const noexcept { for (; first != last; ++first) std::ranges::destroy_at(std::addressof(*first)); return first; } template<no-throw-input-range R> requires std::destructible<std::ranges::range_value_t<R>> constexpr std::ranges::borrowed_iterator_t<R> operator()(R&& r) const noexcept { return operator()(std::ranges::begin(r), std::ranges::end(r)); } }; inline constexpr destroy_fn destroy{}; |
[编辑] 示例
以下示例演示如何使用 ranges::destroy
销毁连续的元素序列。
运行此代码
#include <iostream> #include <memory> #include <new> struct Tracer { int value; ~Tracer() { std::cout << value << " destructed\n"; } }; int main() { alignas(Tracer) unsigned char buffer[sizeof(Tracer) * 8]; for (int i = 0; i < 8; ++i) new(buffer + sizeof(Tracer) * i) Tracer{i}; //manually construct objects auto ptr = std::launder(reinterpret_cast<Tracer*>(buffer)); std::ranges::destroy(ptr, ptr + 8); }
输出
0 destructed 1 destructed 2 destructed 3 destructed 4 destructed 5 destructed 6 destructed 7 destructed
[编辑] 参阅
(C++20) |
销毁范围内的多个对象 (算法函数对象) |
(C++20) |
销毁给定地址处的对象 (算法函数对象) |
(C++17) |
销毁对象范围 (函数模板) |