std::ranges::borrowed_iterator_t, std::ranges::borrowed_subrange_t
来自 cppreference.cn
定义于头文件 <ranges> |
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template< ranges::range R > using borrowed_iterator_t = /* see below */; |
(1) | (C++20 起) |
template< ranges::range R > using borrowed_subrange_t = /* see below */; |
(2) | (C++20 起) |
2) 如果
R
满足 borrowed_range
模型,则为 std::ranges::subrange<std::ranges::iterator_t<R>>,否则为 std::ranges::dangling。这两个别名模板被一些 受约束的算法 用于避免返回潜在的悬空迭代器或视图。
[编辑] 可能实现
borrowed_iterator_t |
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template< std::ranges::range R > using borrowed_iterator_t = std::conditional_t<std::ranges::borrowed_range<R>, std::ranges::iterator_t<R>, std::ranges::dangling>; |
borrowed_subrange_t |
template< std::ranges::range R > using borrowed_subrange_t = std::conditional_t<std::ranges::borrowed_range<R>, std::ranges::subrange<std::ranges::iterator_t<R>>, std::ranges::dangling>; |
[编辑] 参阅
(C++20) |
一个占位符类型,指示迭代器或 subrange 不应返回,因为它会悬空(class) |