std::ranges::borrowed_iterator_t, std::ranges::borrowed_subrange_t
来自 cppreference.cn
定义于头文件 <ranges> |
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template< ranges::range R > using borrowed_iterator_t = /* see below */; |
(1) | (自 C++20 起) |
template< ranges::range R > using borrowed_subrange_t = /* see below */; |
(2) | (自 C++20 起) |
2) std::ranges::subrange<std::ranges::iterator_t<R>> 如果
R
模型 borrowed_range
,则为 std::ranges::dangling,否则。这两个别名模板被一些约束算法使用,以避免返回可能悬垂的迭代器或视图。
[edit] 可能的实现
borrowed_iterator_t |
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template< std::ranges::range R > using borrowed_iterator_t = std::conditional_t<std::ranges::borrowed_range<R>, std::ranges::iterator_t<R>, std::ranges::dangling>; |
borrowed_subrange_t |
template< std::ranges::range R > using borrowed_subrange_t = std::conditional_t<std::ranges::borrowed_range<R>, std::ranges::subrange<std::ranges::iterator_t<R>>, std::ranges::dangling>; |
[edit] 参见
(C++20) |
一个占位符类型,指示不应返回迭代器或 subrange ,因为它会是悬垂的(类) |