stdc_leading_zeros
来自 cppreference.cn
定义于头文件 <stdbit.h> |
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unsigned int stdc_leading_zeros_uc( unsigned char value ) [[unsequenced]]; |
(1) | (自 C23 起) |
unsigned int stdc_leading_zeros_us( unsigned short value ) [[unsequenced]]; |
(2) | (自 C23 起) |
unsigned int stdc_leading_zeros_ui( unsigned int value ) [[unsequenced]]; |
(3) | (自 C23 起) |
unsigned int stdc_leading_zeros_ul( unsigned long int value ) [[unsequenced]]; |
(4) | (自 C23 起) |
unsigned int stdc_leading_zeros_ull( unsigned long long int value ) [[unsequenced]]; |
(5) | (自 C23 起) |
#define stdc_leading_zeros( value ) // 暴露的接口 |
(6) | (自 C23 起) |
1-5) 返回 value 中从最高有效位开始的连续 0 位的数量。
6) 类型泛型函数(由其
generic_value_type
参数标记)根据输入值的类型返回适当的值,只要它是- 标准无符号整数类型,排除 bool;
- 扩展无符号整数类型;
- 或者,位精确无符号整数类型,其宽度与标准或扩展整数类型匹配,排除 bool。
generic_return_type
应为能够表示计算结果的适当大小的无符号整数类型。目录 |
[编辑] 参数
value | - | 无符号整数类型的值 |
[编辑] 返回值
value 中从最高有效位开始的连续 0 位的数量。
[编辑] 示例
运行此代码
#include <limits.h> #include <stdbit.h> #include <stdint.h> #include <stdio.h> #define bits_num(value) (sizeof(value) * CHAR_BIT) #define bin_impl(T, suffix) \ const char* bin_##suffix(T x) \ { \ static char buf[bits_num(x) * CHAR_BIT + 1]; \ for (T i = 0, mask = ((T)1 << (bits_num(x) - 1)); mask; mask >>= 1) \ buf[i++] = x & mask ? '1' : '0'; \ buf[bits_num(x)] = '\0'; \ return buf; \ } bin_impl(uint8_t, u8) bin_impl(uint16_t, u16) bin_impl(uint32_t, u32) bin_impl(uint64_t, u64) #define bin(x) _Generic((x), \ uint8_t: bin_u8, uint16_t: bin_u16, uint32_t: bin_u32, default: bin_u64)(x) int main() { puts("uint8_t:"); for (uint8_t x = 0b11000000; ; x >>= 1) { printf("x = [%s], leading zeros: %d\n", bin(x), stdc_leading_zeros(x)); if (!x) break; } puts("uint16_t:"); for (uint16_t x = 0b11000000; ; x >>= 1) { printf("x = [%s], leading zeros: %d\n", bin(x), stdc_leading_zeros(x)); if (!x) break; } }
输出
uint8_t: x = [11000000], leading zeros: 0 x = [01100000], leading zeros: 1 x = [00110000], leading zeros: 2 x = [00011000], leading zeros: 3 x = [00001100], leading zeros: 4 x = [00000110], leading zeros: 5 x = [00000011], leading zeros: 6 x = [00000001], leading zeros: 7 x = [00000000], leading zeros: 8 uint16_t: x = [0000000011000000], leading zeros: 8 x = [0000000001100000], leading zeros: 9 x = [0000000000110000], leading zeros: 10 x = [0000000000011000], leading zeros: 11 x = [0000000000001100], leading zeros: 12 x = [0000000000000110], leading zeros: 13 x = [0000000000000011], leading zeros: 14 x = [0000000000000001], leading zeros: 15 x = [0000000000000000], leading zeros: 16
[编辑] 参见
查找从最高有效位开始的第一个 0 位的位置 (类型泛型函数宏) | |
(C23) |
计算无符号整数中 0 位的数量 (类型泛型函数宏) |
(C23) |
计算从最高有效位开始的连续 1 位的数量 (类型泛型函数宏) |
C++ 文档 关于 countl_zero
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