std::ranges::adjacent_view<V,N>::size
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< cpp | ranges | adjacent view
constexpr auto size() requires ranges::sized_range<V>; |
(自 C++23 起) | |
constexpr auto size() const requires ranges::sized_range<const V>; |
(自 C++23 起) | |
返回元素数量。
令 base_
为底层视图。等效于
using SizeType = decltype(ranges::size(base_)); using CommonType = ranges::common_type_t<SizeType, std::size_t>; auto size = static_cast<CommonType>(ranges::size(base_)); size -= std::min<CommonType>(size, N - 1); return static_cast<SizeType>(size);
内容 |
[编辑] 参数
(无)
[编辑] 返回值
元素数量,如果 0 为 ranges::size(base_) 小于 N 则可能为 0。
[编辑] 示例
运行此代码
#include <ranges> int main() { constexpr static auto v = {1, 2, 3, 4, 5, 6}; constexpr int width1 {4}; constexpr auto view1 {std::views::adjacent<width1>(v)}; static_assert(view1.size() == 3); static_assert(view1.size() == (v.size() - width1 + 1)); constexpr int width2 {8}; constexpr auto view2 {std::views::adjacent<width2>(v)}; // window is too wide, so view2 has no elements: static_assert(view2.size() == 0); }
[编辑] 另请参阅
(C++20) |
返回一个等于范围大小的整数 (定制点对象) |
(C++20) |
返回一个等于范围大小的有符号整数 (定制点对象) |