std::deque<T,Allocator>::rbegin, std::deque<T,Allocator>::crbegin
来自 cppreference.cn
reverse_iterator rbegin(); |
(1) | (noexcept since C++11) |
const_reverse_iterator rbegin() const; |
(2) | (noexcept since C++11) |
const_reverse_iterator crbegin() const noexcept; |
(3) | (since C++11) |
返回指向反向 deque
的首元素的逆向迭代器。它对应于非反向 deque
的末元素。如果 deque
为空,则返回的迭代器等于 rend()。
目录 |
[编辑] 返回值
指向首元素的逆向迭代器。
[编辑] 复杂度
常数。
[编辑] 注解
返回的逆向迭代器的底层迭代器是end 迭代器。 因此,如果 end 迭代器失效,则返回的迭代器也会失效。
libc++ 将 crbegin()
向后移植到 C++98 模式。
[编辑] 示例
运行此代码
#include <algorithm> #include <iostream> #include <numeric> #include <string> #include <deque> int main() { std::deque<int> nums{1, 2, 4, 8, 16}; std::deque<std::string> fruits{"orange", "apple", "raspberry"}; std::deque<char> empty; // Print deque. std::for_each(nums.rbegin(), nums.rend(), [](const int n) { std::cout << n << ' '; }); std::cout << '\n'; // Sums all integers in the deque nums (if any), printing only the result. std::cout << "Sum of nums: " << std::accumulate(nums.rbegin(), nums.rend(), 0) << '\n'; // Prints the first fruit in the deque fruits, checking if there is any. if (!fruits.empty()) std::cout << "First fruit: " << *fruits.rbegin() << '\n'; if (empty.rbegin() == empty.rend()) std::cout << "deque 'empty' is indeed empty.\n"; }
输出
16 8 4 2 1 Sum of nums: 31 First fruit: raspberry deque 'empty' is indeed empty.
[编辑] 参见
(C++11) |
返回指向末尾的逆向迭代器 (公共成员函数) |
(C++14) |
返回指向容器或数组开头的逆向迭代器 (函数模板) |