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std::chrono::duration<Rep,Period>::运算符+=, -=, *=, /=, %=

来自 cppreference.cn
< cpp‎ | chrono‎ | duration
 
 
 
 
(1)
duration& operator+=( const duration& d );
(since C++11)
(constexpr since C++17)
(2)
duration& operator-=( const duration& d );
(since C++11)
(constexpr since C++17)
(3)
duration& operator*=( const rep& rhs );
(since C++11)
(constexpr since C++17)
(4)
duration& operator/=( const rep& rhs );
(since C++11)
(constexpr since C++17)
(5)
duration& operator%=( const rep& rhs );
(since C++11)
(constexpr since C++17)
(6)
duration& operator%=( const duration& rhs );
(since C++11)
(constexpr since C++17)

对具有相同周期的两个 duration 对象之间或 duration 对象与节拍计数值之间执行复合赋值。

如果 rep_ 是保存此 duration 对象中节拍数的成员变量,

1) 等价于 rep_ += d.count(); return *this;
2) 等价于 rep_ -= d.count(); return *this;
3) 等价于 rep_ *= rhs; return *this;
4) 等价于 rep_ /= rhs; return *this;
5) 等价于 rep_ %= rhs; return *this;
6) 等价于 rep_ %= d.count(); return *this;

目录

[编辑] 参数

d - 运算符右侧的 duration 对象
rhs - 运算符右侧的节拍数

[编辑] 返回值

修改后对此 duration 对象的引用。

[编辑] 示例

#include <chrono>
#include <iostream>
 
int main()
{
    std::chrono::minutes m(11);
    m *= 2;
    m += std::chrono::hours(10); // hours implicitly convert to minutes
    std::cout << m.count() << " minutes equals "
              << std::chrono::duration_cast<std::chrono::hours>(m).count() 
              << " hours and ";
    m %= std::chrono::hours(1);
    std::cout << m.count() << " minutes\n";
}

输出

622 minutes equals 10 hours and 22 minutes

[编辑] 参见

递增或递减节拍数
(public member function) [编辑]
实现以 duration 对象作为参数的算术运算
(function template) [编辑]