命名空间
变体
操作

std::unordered_set<Key,Hash,KeyEqual,Allocator>::begin, std::unordered_set<Key,Hash,KeyEqual,Allocator>::cbegin

来自 cppreference.cn
 
 
 
 
iterator begin() noexcept;
(1) (since C++11)
const_iterator begin() const noexcept;
(2) (since C++11)
const_iterator cbegin() const noexcept;
(3) (since C++11)

返回指向 unordered_set 首个元素的迭代器。

如果 unordered_set 为空,则返回的迭代器将等于 end()

range-begin-end.svg

目录

[edit] 返回值

指向首个元素的迭代器。

[edit] 复杂度

常数。

注意

由于 iteratorconst_iterator 都是常量迭代器(并且实际上可能是相同的类型),因此无法通过任何这些成员函数返回的迭代器来修改容器的元素。

[edit] 示例

#include <iostream>
#include <unordered_set>
 
struct Point { double x, y; };
 
int main()
{
    Point pts[3] = {{1, 0}, {2, 0}, {3, 0}};
 
    // points is a set containing the addresses of points
    std::unordered_set<Point*> points = { pts, pts + 1, pts + 2 };
 
    // Change each y-coordinate of (i, 0) from 0 into i^2 and print the point
    for (auto iter = points.begin(); iter != points.end(); ++iter)
    {
        (*iter)->y = ((*iter)->x) * ((*iter)->x); // iter is a pointer-to-Point*
        std::cout << "(" << (*iter)->x << ", " << (*iter)->y << ") ";
    }
    std::cout << '\n';
 
    // Now using the range-based for loop, we increase each y-coordinate by 10
    for (Point* i : points)
    {
        i->y += 10;
        std::cout << "(" << i->x << ", " << i->y << ") ";
    }
}

可能的输出

(3, 9) (1, 1) (2, 4) 
(3, 19) (1, 11) (2, 14)

[edit] 参见

返回指向末尾的迭代器
(public member function) [edit]
(C++11)(C++14)
返回指向容器或数组开头的迭代器
(function template) [edit]