std::erase_if (std::multimap)
来自 cppreference.cn
定义于头文件 <map> |
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template< class Key, class T, class Compare, class Alloc, class Pred > |
(since C++20) | |
从 c 中擦除所有满足谓词 pred 的元素。
等价于
auto old_size = c.size(); for (auto first = c.begin(), last = c.end(); first != last;) { if (pred(*first)) first = c.erase(first); else ++first; } return old_size - c.size();
目录 |
[edit] 参数
c | - | 要从中擦除元素的容器 |
pred | - | 谓词,如果元素应被擦除则返回 true |
[edit] 返回值
被擦除元素的数量。
[edit] 复杂度
线性。
[edit] 示例
运行此代码
#include <iostream> #include <map> void println(auto rem, auto const& container) { std::cout << rem << '{'; for (char sep[]{0, ' ', 0}; const auto& [key, value] : container) std::cout << sep << '{' << key << ", " << value << '}', *sep = ','; std::cout << "}\n"; } int main() { std::multimap<int, char> data { {1, 'a'}, {2, 'b'}, {3, 'c'}, {4, 'd'}, {5, 'e'}, {4, 'f'}, {5, 'g'}, {5, 'g'}, }; println("Original:\n", data); const auto count = std::erase_if(data, [](const auto& item) { auto const& [key, value] = item; return (key & 1) == 1; }); println("Erase items with odd keys:\n", data); std::cout << count << " items removed.\n"; }
输出
Original: {{1, a}, {2, b}, {3, c}, {4, d}, {4, f}, {5, e}, {5, g}, {5, g}} Erase items with odd keys: {{2, b}, {4, d}, {4, f}} 5 items removed.
[edit] 参见
移除满足特定标准的元素 (函数模板) | |
(C++20)(C++20) |
移除满足特定标准的元素 (算法函数对象) |