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std::chrono::year_month_day_last::operator+=, std::chrono::year_month_day_last::operator-=

来自 cppreference.cn
 
 
 
 
constexpr std::chrono::year_month_day_last&
    operator+=( const std::chrono::years& dy ) const noexcept;
(1) (since C++20)
constexpr std::chrono::year_month_day_last&
    operator+=( const std::chrono::months& dm ) const noexcept;
(2) (since C++20)
constexpr std::chrono::year_month_day_last&
    operator-=( const std::chrono::years& dy ) const noexcept;
(3) (since C++20)
constexpr std::chrono::year_month_day_last&
    operator-=( const std::chrono::months& dm ) const noexcept;
(4) (since C++20)

通过时长 dy 或 dm 修改 *this 所代表的时间点。

1) 等价于 *this = *this + dy;
2) 等价于 *this = *this + dm;
3) 等价于 *this = *this - dy;
4) 等价于 *this = *this - dm;

对于可转换为 std::chrono::years 和 std::chrono::months 的时长,如果调用在其他情况下会是模棱两可的,则优先选择 years 重载 (1,3)。

[edit] 示例

#include <cassert>
#include <chrono>
 
int main()
{
    auto ymdl{11/std::chrono::last/2020};
 
    ymdl += std::chrono::years(15);
    assert(ymdl.day() == std::chrono::day(30));
    assert(ymdl.month() == std::chrono::November);
    assert(ymdl.year() == std::chrono::year(2035));
 
    ymdl -= std::chrono::months(6);
    assert(ymdl.day() == std::chrono::day(31));
    assert(ymdl.month() == std::chrono::May);
    assert(ymdl.year() == std::chrono::year(2035));
}

[edit] 参见

添加或减去年份或月份到 year_month_day_last
(函数) [edit]