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std::chrono::year_month::operator+=, std::chrono::year_month::operator-=

来自 cppreference.cn
< cpp‎ | chrono‎ | year month
 
 
 
 
constexpr std::chrono::year_month&
    operator+=( const std::chrono::years& dy ) const noexcept;
(1) (since C++20)
constexpr std::chrono::year_month&
    operator+=( const std::chrono::months& dm ) const noexcept;
(2) (since C++20)
constexpr std::chrono::year_month&
    operator-=( const std::chrono::years& dy ) const noexcept;
(3) (since C++20)
constexpr std::chrono::year_month&
    operator-=( const std::chrono::months& dm ) const noexcept;
(4) (since C++20)

通过持续时间 *this 代表的时间点。

1) 等价于 *this = *this + dy;
2) 等价于 *this = *this + dm;
3) 等价于 *this = *this - dy;
4) 等价于 *this = *this - dm;

对于可以转换为 std::chrono::yearsstd::chrono::months 的持续时间,如果调用在其他情况下会产生歧义,则优先选择 years 重载 (1,3)

[编辑] 示例

#include <cassert>
#include <chrono>
 
int main()
{
    auto ym{std::chrono::day(1)/7/2023};
 
    ym -= std::chrono::years{2};
    assert(ym.month() == std::chrono::July);
    assert(ym.year() == std::chrono::year(2021));
 
    ym += std::chrono::months{7};
    assert(ym.month() == std::chrono::month(2));
    assert(ym.year() == std::chrono::year(2022));
}

[编辑] 参见

year_month 执行算术运算
(函数) [编辑]