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std::chrono::weekday::operator+=, std::chrono::weekday::operator-=

来自 cppreference.cn
< cpp‎ | chrono‎ | weekday
 
 
 
 
constexpr std::chrono::weekday& operator+=( const std::chrono::days& d ) noexcept;
(1) (C++20 起)
constexpr std::chrono::weekday& operator-=( const std::chrono::days& d ) noexcept;
(2) (C++20 起)

从星期几值中加上或减去 d.count(),并将结果对 7 取模,得到一个在 [06] 范围内的整数。

1) 执行 *this = *this + d;
2) 执行 *this = *this - d;

目录

[编辑] 返回值

对修改后的此 weekday 的引用。

[编辑] 注意

在调用这些函数之一后,如果操作期间没有发生溢出,则 ok() 始终为 true。

[编辑] 示例

#include <chrono>
#include <iostream>
 
int main()
{
    std::cout << std::boolalpha;
 
    std::chrono::weekday wd{5}; // Friday is 5
    wd += std::chrono::days(2);
    std::cout << (wd == std::chrono::weekday(0)) << ' '
              << (wd == std::chrono::Sunday) << ' ';
 
    wd -= std::chrono::days(3);
    std::cout << (wd == std::chrono::weekday(4)) << ' '
              << (wd == std::chrono::Thursday) << ' ';
 
    wd = std::chrono::Wednesday;
    wd += std::chrono::days{8}; // ((3 += 8 == 11) % 7) == 4;
    std::cout << (wd == std::chrono::Thursday) << ' ';
 
    wd -= (std::chrono::Sunday - std::chrono::Tuesday); // -= -2
    // (4 -= -2) == 6
    std::cout << (wd == std::chrono::Saturday) << '\n';
}

输出

true true true true true true

[编辑] 参阅

增加或减少星期几
(public member function) [编辑]
weekday 进行算术运算
(function) [编辑]